1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
|
; This testcase tests to see if adds and PHI's are handled in their full
; generality. This testcase comes from the following C code:
;
; void f() {
; int i;
; for (i = 1; i < 100; i++) {
; if (i)
; g();
; }
; }
;
; Note that this is a "feature" test, not a correctness test.
;
; RUN: llvm-as < %s | opt -cee -simplifycfg | llvm-dis | not grep cond213
;
implementation ; Functions:
declare void %g()
void %f() {
bb0: ; No predecessors!
br label %bb2
bb2: ; preds = %bb4, %bb0
%cann-indvar = phi int [ 0, %bb0 ], [ %add1-indvar, %bb4 ] ; <int> [#uses=2]
%add1-indvar = add int %cann-indvar, 1 ; <int> [#uses=2]
%cond213 = seteq int %add1-indvar, 0 ; <bool> [#uses=1]
br bool %cond213, label %bb4, label %bb3
bb3: ; preds = %bb2
call void %g( )
br label %bb4
bb4: ; preds = %bb3, %bb2
%reg109 = add int %cann-indvar, 2 ; <int> [#uses=1]
%cond217 = setle int %reg109, 99 ; <bool> [#uses=1]
br bool %cond217, label %bb2, label %bb5
bb5: ; preds = %bb4
ret void
}
|
