When an instruction like: A += B had both A and B virtual registers

spilled, A was loaded from its stack location twice. This fixes the bug.


git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@11093 91177308-0d34-0410-b5e6-96231b3b80d8

1 files changed, 18 insertions, 0 deletions

diff --git a/lib/CodeGen/MachineInstr.cpp b/lib/CodeGen/MachineInstr.cpp
index 9d7b1b2d99..869d963d53 100644
--- a/lib/CodeGen/MachineInstr.cpp
+++ b/lib/CodeGen/MachineInstr.cpp
@@ -27,6 +27,24 @@ namespace llvm {
 //
 extern const TargetInstrDescriptor *TargetInstrDescriptors;
 
+bool MachineOperand::isEverUsed(const MachineInstr& mi) const
+{
+    for (int i = 0, e = mi.getNumOperands(); i != e; ++i) {
+        if (*this == mi.getOperand(i) && mi.getOperand(i).isUse())
+            return true;
+    }
+    return false;
+}
+
+bool MachineOperand::isEverDefined(const MachineInstr& mi) const
+{
+    for (int i = 0, e = mi.getNumOperands(); i != e; ++i) {
+        if (*this == mi.getOperand(i) && mi.getOperand(i).isDef())
+            return true;
+    }
+    return false;
+}
+
 // Constructor for instructions with variable #operands
 MachineInstr::MachineInstr(MachineOpCode OpCode, unsigned  numOperands)
   : opCode(OpCode),