diff options
author | Vassili Karpov <av1474@comtv.ru> | 2007-02-28 20:13:45 -0800 |
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committer | Linus Torvalds <torvalds@woody.linux-foundation.org> | 2007-03-01 14:53:39 -0800 |
commit | 48dba8ab9b93c3b6b57946bd45ae013402b0b054 (patch) | |
tree | 778ecc093541ba14f70bfdeb8f4e79a77d95f2a6 | |
parent | 7355690ead6d61f6344072ae61060f985060da29 (diff) |
[PATCH] Documentation: CPU load calculation description
Describes how/when the information exported to `/proc/stat' is calculated,
and possible problems with this approach.
Signed-off-by: Vassili Karpov <av1474@comtv.ru>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
-rw-r--r-- | Documentation/cpu-load.txt | 113 |
1 files changed, 113 insertions, 0 deletions
diff --git a/Documentation/cpu-load.txt b/Documentation/cpu-load.txt new file mode 100644 index 00000000000..287224e57cf --- /dev/null +++ b/Documentation/cpu-load.txt @@ -0,0 +1,113 @@ +CPU load +-------- + +Linux exports various bits of information via `/proc/stat' and +`/proc/uptime' that userland tools, such as top(1), use to calculate +the average time system spent in a particular state, for example: + + $ iostat + Linux 2.6.18.3-exp (linmac) 02/20/2007 + + avg-cpu: %user %nice %system %iowait %steal %idle + 10.01 0.00 2.92 5.44 0.00 81.63 + + ... + +Here the system thinks that over the default sampling period the +system spent 10.01% of the time doing work in user space, 2.92% in the +kernel, and was overall 81.63% of the time idle. + +In most cases the `/proc/stat' information reflects the reality quite +closely, however due to the nature of how/when the kernel collects +this data sometimes it can not be trusted at all. + +So how is this information collected? Whenever timer interrupt is +signalled the kernel looks what kind of task was running at this +moment and increments the counter that corresponds to this tasks +kind/state. The problem with this is that the system could have +switched between various states multiple times between two timer +interrupts yet the counter is incremented only for the last state. + + +Example +------- + +If we imagine the system with one task that periodically burns cycles +in the following manner: + + time line between two timer interrupts +|--------------------------------------| + ^ ^ + |_ something begins working | + |_ something goes to sleep + (only to be awaken quite soon) + +In the above situation the system will be 0% loaded according to the +`/proc/stat' (since the timer interrupt will always happen when the +system is executing the idle handler), but in reality the load is +closer to 99%. + +One can imagine many more situations where this behavior of the kernel +will lead to quite erratic information inside `/proc/stat'. + + +/* gcc -o hog smallhog.c */ +#include <time.h> +#include <limits.h> +#include <signal.h> +#include <sys/time.h> +#define HIST 10 + +static volatile sig_atomic_t stop; + +static void sighandler (int signr) +{ + (void) signr; + stop = 1; +} +static unsigned long hog (unsigned long niters) +{ + stop = 0; + while (!stop && --niters); + return niters; +} +int main (void) +{ + int i; + struct itimerval it = { .it_interval = { .tv_sec = 0, .tv_usec = 1 }, + .it_value = { .tv_sec = 0, .tv_usec = 1 } }; + sigset_t set; + unsigned long v[HIST]; + double tmp = 0.0; + unsigned long n; + signal (SIGALRM, &sighandler); + setitimer (ITIMER_REAL, &it, NULL); + + hog (ULONG_MAX); + for (i = 0; i < HIST; ++i) v[i] = ULONG_MAX - hog (ULONG_MAX); + for (i = 0; i < HIST; ++i) tmp += v[i]; + tmp /= HIST; + n = tmp - (tmp / 3.0); + + sigemptyset (&set); + sigaddset (&set, SIGALRM); + + for (;;) { + hog (n); + sigwait (&set, &i); + } + return 0; +} + + +References +---------- + +http://lkml.org/lkml/2007/2/12/6 +Documentation/filesystems/proc.txt (1.8) + + +Thanks +------ + +Con Kolivas, Pavel Machek |