diff options
author | Duncan Sands <baldrick@free.fr> | 2011-10-27 19:16:21 +0000 |
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committer | Duncan Sands <baldrick@free.fr> | 2011-10-27 19:16:21 +0000 |
commit | 32a43cc0fc3cd42702d7859eaa58dd42f561a54d (patch) | |
tree | 56449a56539910bed314212d85f556a4d59768c0 /lib/Analysis/InstructionSimplify.cpp | |
parent | 6eb1ed8c9c6a6d3f9b57900c44fc076d08a358bd (diff) |
Reapply commit 143028 with a fix: the problem was casting a ConstantExpr Mul
using BinaryOperator (which only works for instructions) when it should have
been a cast to OverflowingBinaryOperator (which also works for constants).
While there, correct a few other dubious looking uses of BinaryOperator.
Thanks to Chad Rosier for the testcase. Original commit message:
My super-optimizer noticed that we weren't folding this expression to
true: (x *nsw x) sgt 0, where x = (y | 1). This occurs in 464.h264ref.
git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@143125 91177308-0d34-0410-b5e6-96231b3b80d8
Diffstat (limited to 'lib/Analysis/InstructionSimplify.cpp')
-rw-r--r-- | lib/Analysis/InstructionSimplify.cpp | 5 |
1 files changed, 3 insertions, 2 deletions
diff --git a/lib/Analysis/InstructionSimplify.cpp b/lib/Analysis/InstructionSimplify.cpp index d9e3400f89..31cbbba596 100644 --- a/lib/Analysis/InstructionSimplify.cpp +++ b/lib/Analysis/InstructionSimplify.cpp @@ -758,7 +758,8 @@ static Value *SimplifyMulInst(Value *Op0, Value *Op1, const TargetData *TD, Value *X = 0, *Y = 0; if ((match(Op0, m_IDiv(m_Value(X), m_Value(Y))) && Y == Op1) || // (X / Y) * Y (match(Op1, m_IDiv(m_Value(X), m_Value(Y))) && Y == Op0)) { // Y * (X / Y) - BinaryOperator *Div = cast<BinaryOperator>(Y == Op1 ? Op0 : Op1); + PossiblyExactOperator *Div = + cast<PossiblyExactOperator>(Y == Op1 ? Op0 : Op1); if (Div->isExact()) return X; } @@ -842,7 +843,7 @@ static Value *SimplifyDiv(Instruction::BinaryOps Opcode, Value *Op0, Value *Op1, Value *X = 0, *Y = 0; if (match(Op0, m_Mul(m_Value(X), m_Value(Y))) && (X == Op1 || Y == Op1)) { if (Y != Op1) std::swap(X, Y); // Ensure expression is (X * Y) / Y, Y = Op1 - BinaryOperator *Mul = cast<BinaryOperator>(Op0); + OverflowingBinaryOperator *Mul = cast<OverflowingBinaryOperator>(Op0); // If the Mul knows it does not overflow, then we are good to go. if ((isSigned && Mul->hasNoSignedWrap()) || (!isSigned && Mul->hasNoUnsignedWrap())) |