Give CanQual<T> an implicit conversion to bool, so that it can be used

in "if" statements like:

  if (CanQual<ReferenceType> RefType = T.getAs<ReferenceType>())

Thanks to Clang for pointing out this mistake :)


git-svn-id: https://llvm.org/svn/llvm-project/cfe/trunk@86995 91177308-0d34-0410-b5e6-96231b3b80d8

1 files changed, 1 insertions, 1 deletions

diff --git a/lib/Sema/SemaDeclCXX.cpp b/lib/Sema/SemaDeclCXX.cpp
index d094ea4b0f..84934f5baf 100644
--- a/lib/Sema/SemaDeclCXX.cpp
+++ b/lib/Sema/SemaDeclCXX.cpp
@@ -4014,7 +4014,7 @@ bool Sema::CheckOverloadedOperatorDeclaration(FunctionDecl *FnDecl) {
     if (!ResultTy->isDependentType() && ResultTy != Context.VoidPtrTy)
       return Diag(FnDecl->getLocation(),
                   diag::err_operator_new_result_type) << FnDecl->getDeclName()
-                  << Context.VoidPtrTy;
+                  << static_cast<QualType>(Context.VoidPtrTy);
     return ret;
   }