The paired 'operator delete' for a placement 'operator new' is always a

placement 'operator delete', even if there are no placement args (i.e.
overload resolution selected an operator new with default arguments).



git-svn-id: https://llvm.org/svn/llvm-project/cfe/trunk@113861 91177308-0d34-0410-b5e6-96231b3b80d8

1 files changed, 8 insertions, 1 deletions

diff --git a/lib/Sema/SemaExprCXX.cpp b/lib/Sema/SemaExprCXX.cpp
index e03c5721c6..6d8c914654 100644
--- a/lib/Sema/SemaExprCXX.cpp
+++ b/lib/Sema/SemaExprCXX.cpp
@@ -1046,7 +1046,14 @@ bool Sema::FindAllocationFunctions(SourceLocation StartLoc, SourceRange Range,
 
   llvm::SmallVector<std::pair<DeclAccessPair,FunctionDecl*>, 2> Matches;
 
-  if (NumPlaceArgs > 0) {
+  // Whether we're looking for a placement operator delete is dictated
+  // by whether we selected a placement operator new, not by whether
+  // we had explicit placement arguments.  This matters for things like
+  //   struct A { void *operator new(size_t, int = 0); ... };
+  //   A *a = new A()
+  bool isPlacementNew = (NumPlaceArgs > 0 || OperatorNew->param_size() != 1);
+
+  if (isPlacementNew) {
     // C++ [expr.new]p20:
     //   A declaration of a placement deallocation function matches the
     //   declaration of a placement allocation function if it has the